Launching default application for given type of file, OS X

Question

I'm writing a python script that generates html file. Every time I run this script I'd like at the end to open default system browser for this file. It's all in OS X environment.

What python code can launch Safari/Firefox/whatever is system default html viewer and open given file? subprocess.call doesn't seem to do the trick.

Answer 1

Do you know about the open command in Mac OS X? I think you can solve your problem by calling it from Python.

man open for details:

The open command opens a file (or a directory or URL), just as if you had double-clicked the file's icon. If no application name is specified, the default application as determined via LaunchServices is used to open the specified files.

Answer 2

What python code can launch Safari/Firefox/whatever is system default html viewer and open given file?

There is a webbrowser module in python, try this:

import webbrowser
webbrowser.open('file://%s' % path)

This will open a new tab in the default browser. There are methods to open a new tab, new window and other options.

Answer 3

import ic

ic.launchurl('file:///somefile.html')