cat filename.* > Datei

Question

I'm looking to translate the unix-command

$ cat filename.* > Datei

into a Python program. Can somebody help ?

Answer 1

Something like this should get you started:

import glob

outfile = file("Datei", "wb")
for f in glob.glob("filename.*"):
  infile = open(f, "rb")
  outfile.write(infile.read())
  infile.close()
outfile.close()

UPDATE: Of course, input files need to be opened, too.

UPDATE: Explicitly use binary mode.

Answer 2

import glob

output = open('Datei', 'wb')
chunk_size = 8192
for filename in glob.glob('filename.*'):
    input = open(filename, 'rb')
    buffer = input.read(chunk_size)
    while buffer: # False if buffer == ""
        output.write(buffer)
        buffer = input.read(chunk_size)
    input.close()
output.close()

Answer 3

alternatively

import os
f=open("outfile.txt","a")
for file in os.listdir("."):
    if file.startswith("filename."):
         for line in open(file):
               f.write(line)
f.close()

Answer 4

Thank you for your help. My script now:

LOGFILEDIR="/olatfile/logs"
VORMONAT=time.strftime("%Y-%m", time.localtime(time.time()-3600*24*30))
LOGDATEIEN=LOGFILEDIR+"/olat.log."+VORMONAT +"-*"
print LOGDATEIEN
OUTPUT=LOGFILEDIR+"/olat.log."+VORMONAT
LOGFILE=OUTPUT
output = open(OUTPUT, 'wb')
chunk_size = 8096
for filename in glob.glob(LOGDATEIEN):
input = open(filename, 'rb')
buffer = input.read(chunk_size)
while len(buffer) > 0:
output.write(buffer)
buffer = input.read(chunk_size)
input.close()
output.close()

An application create everyday a logfile like "olat.log.07-12-2009" My idea was to cat all the logs from one moth into one logfile and analyze this one.