mysqli query, LIKE and AND in the same query doesn't work out like it should

Question

so this is my query, it doesn't matter if approved is set to 0 or 1 it will give me all the rows anyway

SELECT * 
FROM `tutorials` 
WHERE tags LIKE '% php %' OR tags LIKE 'php %' OR tags LIKE '% php' OR tags = 'php' 
AND approved=1

I guess it's because of the OR but I might be wrong, if someone could help me out on this :)

Answer 1

Try brackets

SELECT * 
FROM `tutorials` 
WHERE   (  tags LIKE '% php %' 
      OR tags LIKE 'php %' 
      OR tags LIKE '% php' 
      OR tags = 'php' 
     )
AND approved=1

Answer 2

I didnt get what you exactly want. But this may be the one that you are looking for

SELECT * FROM tutorials WHERE ( tags LIKE '% php %' OR tags LIKE 'php %' OR tags LIKE '% php' OR tags = 'php' ) AND approved=1

Answer 3

I think you are missing some colons:

SELECT * 
FROM `tutorials` 
WHERE (tags LIKE '% php %' OR tags LIKE 'php %' OR tags LIKE '% php' OR tags = 'php')
AND approved=1

The reason you should include colons, is because OR and AND operators are on the same level of precedence. When you omit the colons, your query would be parsed as:

SELECT * 
FROM `tutorials` 
WHERE (tags LIKE '% php %' OR (tags LIKE 'php %' OR (tags LIKE '% php' OR (tags = 'php' 
AND approved=1))))

Especially when using long lists of OR and AND operators in a query, it is advisable to use colons to make your intent clear. For a full list of the operator precedence in MySQL (which is generally common to other SQL dialects), see the MySQL manual.