"[" is not classed a unicode character http://en.wikipedia.org/wiki/List%5Fof%5FUnicode%5Fcharacters (my guess) as to why this wouldn't work:
declare @v nvarchar(255)
set @v = '[x]825'
select 1
where @v like '[x]825'
Ta!
"[" is not classed a unicode character http://en.wikipedia.org/wiki/List%5Fof%5FUnicode%5Fcharacters (my guess) as to why this wouldn't work:
declare @v nvarchar(255)
set @v = '[x]825'
select 1
where @v like '[x]825'
Ta!
[]
defines a range of characters for a pattern match. It has special meaning in a LIKE statement. Here's the documentation for it.
If you're looking for those characters explicitly, you'll need to escape them, like this:
declare @v nvarchar(255)
set @v = '[x]825'
select 1
where @v LIKE '![x]825'
ESCAPE '!'
[x] has a specific meaning to SQL server. The brackets are used for very basic regular expressions. SO what you are searching for is where the first character contains the letter X and of course that isn't the first character in your variable.
It is best not use like unless you intend to havea awildcard and it is a bad practice to have a wildcard be the first character as it makes the query use a table scan instead of an index.