php interface - private / protected

Question

Hi,

Is it possible in PHP 5 to have an interface that has private / protected methods?

Right now I have interface iService { private method1(); }

That throws an error. Just want to confirm that it is the case that interface can only contains public methods.

Thank you, Tee

Answer 1

In general an interface can only have public members, because the only function of an interface is to be inherited.

From PHPfreaks.com tutorial:

PHP5 features interfaces. Not to be confused with interfaces in the more general sense, the interface keyword creates an entity that can be used to enforce a common interface upon classes without having to extend them like with abstract classes. Instead an interface is implemented.

Interfaces are different from abstract classes. For one, they’re not actually classes. They don’t define properties, and they don’t define any behaviour. The methods declared in an interface must be declared in classes that implement it.

Because an interface in the more general sense is a definition of how an object interacts with other code, all methods must be declared public (see section on visibility in this chapter). Using abstract classes, an abstract method can have any visibility, but the extending classes must have their implementations use the same (or weaker) visibility. Implementing an interface adds the methods as abstract methods to the subject class, failure to implement it will result in an error like the following:

Fatal error: Class SomeConcreteClass contains n abstract method(s) and must therefore be declared abstract or implement the remaining methodsYes, abstract classes can implement interfaces.

Answer 2

Interfaces are used to describe public methods of a class implementing that interface. You can never have a private method in an interface. Any methods in an interface are assumed to be in use and should not be changed.

Interfaces is the PHP link, but this is standard in OO programming.

Answer 3

The PHP manual page about interfaces explicitely states :

All methods declared in an interface must be public, this is the nature of an interface.

I guess this explains the error you are getting ;-)

Answer 4

interfaces are type declarations. a type is set of values, plus a set of operations that can be carried upon them from outside. a private method doesn't fit into this picture.

interface T {
  public /*int*/ function f(array $a);
}
interface U {
  public /*T*/ function g(T $t);
}

class C implements U {
    public function g(T $t) {
        ...
        $x = $t->f();
        ...
    }
}

interfaces are useful because they state, well, objects' interfaces. how the objects communicate with their environment.

now let's say T::f could be declared private. how would that be useful to other objects? it would not callable from outside, it would not be part of its interface.