tags:

views:

94

answers:

4

Hi,

I have the following (stripped down) code:

<?PHP
    class A {
     function Show(){
      echo "ciao";
     }
    }

    $a = new A();
    $b = new B();

    class B {
        function __construct() {
            $a->Show();
        }
    }
?>

With a bit of surprise I cannot access the globally defined $a variable from within the class and I get a Undefined variable exception. Any help?

+1  A: 

You will need to define it as a global variable inside the scope of the function you want to use it at.

function __construct() {
    global $a;
    $a->Show();
}
LiraNuna
+1  A: 

Why the surprise? That's a pretty logical variable scope problem there...

I suggest you use either the global keyword or the variable $GLOBALS to access your variable.

EDIT: So, in your case that will be:

global $a;
$a->Show();

or

$GLOBALS['a']->Show();

EDIT 2: And, since Vinko is right, I suggest you take a look at PHP's manual about variable scope.

Franz
It is surprising for people accustomed to languages with implicitly inherited scope, like C.
Vinko Vrsalovic
Gotcha, Vinko. Thanks.
Franz
A: 

please don't use the global method that is being suggested. That makes my stomach hurt.

Pass $a into the constructor of B.

class A {
    function Show(){
            echo "ciao";
    }
}

$a = new A();
$b = new B( $a );

class B {
    function __construct( $a ) {
        $a->Show();
    }
}
Galen
A: 
<?php
class A {
    public function Show(){
      return "ciao";
    }
}

class B {
    function __construct() {
        $a = new A();
        echo $a->Show();
    }
}

$b = new B();
?>
Jay Zeng