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1127

answers:

2

I want to do something like this in Actionscript 3:

if(variable is Object) ...;
else ...;

Where variable could be a String(), Number(), Array(), Object()...

Currently the above check returns true for all of these types, which makes sense. I only want it to return true for objects made with new Object(), however.

Any help would be much appreciated!

+2  A: 

Try something based around one of these:

if (variable.constructor.toString().match(/object/i) == 'Object')

if (variable.constructor.toString().indexOf("Object") != -1)

If the object is an Object() the constructor string will be something like

function Object() { ... }

so you can check for that.

cxfx
+1  A: 

You should try to use this functions - getQualifiedClassName and typeof. Here's a code showing how they behave for different data types you've listed, see the difference for the Array and Numbers especially:

Code:

    var o = new Array();    
trace ("var o = new Array()");
trace (getQualifiedClassName(o));
trace (typeof(o));  
var o = new Object(); 
trace ("var o = new Object();");
trace (getQualifiedClassName(o));
trace (typeof(o));
var o = new String();
trace ("var o = new String()");
trace (getQualifiedClassName(o));
trace (typeof(o));
var o = new Number()
trace ("var o = new Number()");
trace (getQualifiedClassName(o));
trace (typeof(o));    
var o = 3.14;
trace ("var o = 3.14");
trace (getQualifiedClassName(o));
trace (typeof(o));

Result:

var o = new Array()
Array
object
var o = new Object();
Object
object
var o = new String()
String
string
var o = new Number()
int
number
var o = 3.14
Number
number

I assume getQualifiedClassName would be what you're looking for.

Robert Bak
Yep, I actually found out about getQualifiedClassName shortly after, and it is indeed what I was looking for. Thanks for the reply!
Tapio Saarinen