Understanding the UNIX command xargs

Question

I'm pretty much confused on this. Need some clarifications.

Example 1 :

pgrep string | xargs ps

Example 2 :

find . | xargs grep whatever

From Example 1, I gather it's this way:

Search for a "string" which is part of name of running process and return the process-ids of all the matches to 'xargs ps' -> which just appends ps to the matches (which are process-ids themselves) to get the same output as :

ps <processid>

Can someone explain what xargs really does in this case?

From Example 2, I gather it's this way:

It's to search for some "string" recursively from the current working directory. Here, how exactly does 'xargs' work?

I was of the opinion that 'xargs' repeatedly appends data from standard input to the 'argument' given to xargs (which usually is a UNIX command by itself).

From xargs() man page :

xargs reads items from the standard input, delimited by blanks (which can be protected with double or single quotes or a backslash) or newlines, and executes the command (default is /bin/echo) one or more times with any initial-arguments followed by items read from standard input. Blank lines on the standard input are ignored.

Answer 1

xargs is normally used to group arguments together so that you dont get a "too many arguments " error which occurs when you pass a large number of arguments to a command

Answer 2

$ echo 'line1
> line2
> line3
> ...
> lineN ' | xargs cmd1 -a -b

will result in:

$ cmd1 -a -b line1 line2 line3 ... lineN

xargs will break cmd1 ... into several executions of cmd1 if the line count gets too large.

xargs may be used for many other tasks related to passing stdin lines as positional arguments. Take a look at the capital -P option in xargs(1) for running several instances of a command in parallel.

Answer 3

#!/bin/sh
#script to echo out the arguments 1 at a time!
for a in $*
do
    echo $a
done

the command

$sh myscript 1 2 3 4 5

will yield

1
2
3
4
5

but

$sh myscript 1 2 3 4 5 6 7 8 9 10 11

will not work since the max number of parameters is exceeded (im not actually sure what the max is, but lets say its 10 for this example!)

To get around this we could use

#!/bin/sh
#script to echo out the arguments 1 at a time!
for a in $*
do
    echo $a | xargs echo
done

we could then run it like this

 $sh myscript "1 2 3 4 5" "6 7 8 9 10 11"

and get the correct result since there are just 2 parameters

Answer 4

A good example of what xargs does is to try getting sorted checksums for every file in a directory using find.

find . | cksum  | sort

returns just one checksum, and it's not clear what it's the checksum for. Not what we want. The pipe sends the stdout from find into stdin for cksum. What cksum really wants is a list of command line args, e.g.

cksum file001.blah file002.blah  file003.blah

will report three lines, one per file, with the desired checksums. Xargs does the magic trick - converting stdout of the previous program to a temporary and hidden command line to feed to the next. The command line that works is:

find . | xargs cksum | sort

Note no pipe between xargs and cksum.

Answer 5

In general xargs is used like this

prog | xargs utility

where prog is expected to output one or more newline/space separated results. The trick is that xargs does not! nessarly call utility once for each result, instead it splits the result list into sublists and calls utility for every sublist. If you want to force xargs to call utility for every single result you will need to invoke it with xargs -L1.

Note that xargs promises you that the sublist sent to utility is shorter than *ARG_MAX* (this is how it avoids those dreaded Argument list to long errors). You can get the current value of *ARG_MAX* using getconf ARG_MAX