PHP: $date + 1 year?

Question

I'm trying to get a date that is one year from the date I specify.

My code looks like this:

$futureDate=date('Y-m-d',strtotime('+one year',$startDate));

It's returning the wrong date.... any ideas why?

Thanks!

Answer 1

Try: $futureDate=date('Y-m-d',strtotime('+1 year',$startDate));

Answer 2

If you are using PHP 5.3, it is because you need to set the default time zone:

date_default_timezone_set()

Answer 3

Try This

$nextyear  = date("M d,Y",mktime(0, 0, 0, date("m",strtotime($startDate)),   date("d",strtotime($startDate)),   date("Y",strtotime($startDate))+1));

Answer 4

strtotime() is returning bool(false), because it can't parse the string '+one year' (it doesn't understand "one"). false is then being implicitly cast to the integer timestamp 0. It's a good idea to verify strtotime()'s output isn't bool(false) before you go shoving it in other functions.

From the docs:

Return Values

Returns a timestamp on success, FALSE otherwise. Previous to PHP 5.1.0, this function would return -1 on failure.

Answer 5

Try this

$newEndingDate = date("Y-m-d", strtotime(date("Y-m-d", strtotime($StaringDate)) . " + 365 day"));

or

$newEndingDate = date("Y-m-d", strtotime(date("Y-m-d", strtotime($StaringDate)) . " + 1 year"));