splitting integer in python?

Question

my integer input is suppose 12345 , i want to split and put it into an array as 1,2,3,4,5 . How will i be able to do it?

Answer 1

return array as string

>>> list(str(12345))
['1', '2', '3', '4', '5']

return array as integer

>>> map(int,str(12345))
[1, 2, 3, 4, 5]

Answer 2

Strings are just as iterable as arrays, so just convert it to string:

str(12345)

Answer 3

>>> [int(i) for i in str(12345)]

[1, 2, 3, 4, 5]

Answer 4

[int(i) for i in str(number)]

or, if do not want to use a list comprehension or you want to use a base different from 10

from __future__ import division # for compatibility of // between Python 2 and 3
def digits(number, base=10):
    assert number >= 0
    if number == 0:
        return [0]
    l = []
    while number > 0:
        l.append(number % base)
        number = number // base
    return l

Answer 5

like @nd says but using the built-in function of int to convert to a different base

>>> [ int(i,16) for i in '0123456789ABCDEF' ]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]

>>> [int(i,2) for i in "100 010 110 111".split()]
[4, 2, 6, 7]

I don't know what is the final objective but take a look also inside the decimal module of python for doing stuff like

>>> Decimal('3.1415926535') + Decimal('2.7182818285')
Decimal('5.85987')