find word before second comma with regex

Question

I want to store the word before the second comma in a string.

So if the string looks like this: Hello, my name is David, bla bla.

I want to set a variable $test = David

Answer 1

this is web based nice tool which name is txt2re

Answer 2

Your regex could look something like this:

^[^,]*,[^,]*\b(\w+),

Match any sequence of non-commas, followed by the first comma, followed by more non-commas, then a word boundary and your actual word, and then the second comma.

Answer 3

<?php

    $s = "Hello, my name is David, bla bla.";

    preg_match ( "/[^,]*,[^,].* ([^,].*),.*/" , $s, $matches ); 

    // or shorter ..
    preg_match ( "/[^,]*,[^,]*\b(\w+),/" , $s, $matches );

    echo $matches[1];
    // => David

?>

Answer 4

^[^,]*,[^,]*\b(\w+)\b,

^ -- The beginning of the string/line
[^ ] -- Any character not being ...
, -- ... a comma
* -- Zero or more of the preceding
, -- A comma
[^,]* -- Again, any character not being a comma, repeated zero or more times
\b -- A word boundary (zero width)
( ) -- A capturing group
\w -- Any word character
+ -- One or more of the preceding
\b -- A word boundary (zero width)
, -- A comma

Answer 5

$s = "Hello, my name is David, bla bla.";
$s = explode(',', $s);
$s = explode(' ', $s[1]);
$test = $s[sizeof($s)-1];

print $test;
'David'

Answer 6

And here is my approach:

<?php
    $input  = 'Hello, my name is David, bla bla.';
    $tmp    = substr( $input, 0, strpos( $input, ',', strpos( $input, ',' ) + 1 ) );
    $word   = substr( $tmp, strrpos( $tmp, ' ' ) + 1 );
    echo $word;
?>