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How to call XSL template from java code ?

Answer 1

+1 A:

Here's some code for a simple XSL transform, along with some tips for using XSL in Java. And here's another example, complete with an example XML and XSL.

Kaleb Brasee 2009-12-16 16:26:55

Answer 2

+2 A:

You can use the javax.xml.transformer.Transformer API for this.

Here's a basic kickoff example:

Source xmlInput = new StreamSource(new File("c:/path/to/input.xml"));
Source xsl = new StreamSource(new File("c:/path/to/file.xsl"));
Result xmlOutput = new StreamResult(new File("c:/path/to/output.xml"));

try {
    Transformer transformer = TransformerFactory.newInstance().newTransformer(xsl);
    transformer.transform(xmlInput, xmlOutput);
} catch (TransformerException e) {
    // Handle.
}

BalusC 2009-12-16 16:31:45

I do not need to transfer, thanks :)

Mohammed 2009-12-16 16:33:12

It also doesn't transfer. It transforms one XML to other XML based on the given XSLT. That's where XSL is for. What exactly do you need after all? You should have elaborated that in your question. You can eventually change the XML source and/or the XML result.

BalusC 2009-12-16 16:35:54

Thanks, Please see the modified question above :)

Mohammed 2009-12-16 16:37:28

You've edited your topicstart. Sorry, I still don't forsee any problems. Maybe you just want to save the result as HTML. Just change the file extension accordingly, e.g. `output.html`.

BalusC 2009-12-16 16:48:39

Answer 3

A:

Is your question that you have an XSLT which doesn't require an input document? Then just give the Transformer object some kind of minimal document:

transformer.transform(new StreamSource(new StringReader("<empty/>")), yourResult);

Paul Clapham 2009-12-16 21:04:27

But the template requires some input, How to accomplish that?

Mohammed 2009-12-16 23:47:21

That code does provide input. That string is a well-formed XML document. What happened when you tried it?

Paul Clapham 2009-12-17 05:42:54

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How to call XSL template from java code ?

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