How to launch a Python/Tkinter dialog box that self-destructs?

Question

Ok, I would like to put together a Python/Tkinter dialog box that displays a simple message and self-destructs after N seconds. Is there a simple way to do this?

Thanks,

--Steve

Answer 1

You can use the after function to call a fucntion after a delay elapsed and the destroy to close the window.

Here is an example

from Tkinter import *
root = Tk()
prompt = 'hello'
label1 = Label(root, text=prompt, width=len(prompt))
label1.pack()

def close_after_2s():
    root.destroy()

root.after(2000, close_after_2s)
root.mainloop()

Update: The after docstring says:

Call function once after given time.
MS specifies the time in milliseconds. 
FUNC gives the function which shall be called. 
Additional parameters are given as parameters to the function call.
Return identifier to cancel scheduling with after_cancel.

Answer 2

you could also use a thread.
this example uses a Timer to call destroy() after a specified amount of time.

import threading
import Tkinter


root = Tkinter.Tk()
Tkinter.Frame(root, width=250, height=100).pack()
Tkinter.Label(root, text='Hello').place(x=10, y=10)

threading.Timer(3.0, root.destroy).start()

root.mainloop()