Regex Pattern for findin http in PHP

Question

Hello everyone, how can i extract the http from this text?

"Text: Here's 2 free bonuses. http://blablabla.blabla/blabla "

But the url can also be another one.

Finaly After i have the array, wich contains usualy just one url, how can i add it to the above text exactly at the same position? but with html tag <a> the results should look something like this

"Text: Here's 2 free bonuses. 
<a href='http://blablabla.blabla/blabla'&gt;http://blablabla.blabla/blabla&lt;/a&gt; "

Answer 1

This regex should do the trick:

$s= "Text: Here's 2 free bonuses. http://blablabla.blabla/blabla and some more text";
$s2= preg_replace('~(http://\S+)\b~', '<a href="$1">$1</a>', $s);
var_dump($s2);

Answer 2

You can do that using regular expression, and more precisely preg_replace(). The matching expression can be something like :

$pattern = 'http://[a-zA-Z0-9\.\-/]+';

Of course, you can refine it for more precise matching, but this should do the trick. If you want to play with regex, have a look at regexpal, it's a great tool for testing. Then, you can perform the replace ($0 corresponds to the whole matched string :

preg_replace($pattern, '<a href="$0">$0</a>', $yourString);