Disclaimer: Precisely what happens depends on your compiler, architecture, etc. But conceptually here's what's going on:
When you declare a variable within a method, it is allocated on the stack. Allocating something on the stack only involves bumping up the stack pointer by the size of the variable. So, for example, if SP
represents the memory address of the top of the stack, declaring char x
results in SP += 1
and int x
results in SP += 4
(on a 32 bit machine).
When the function exits, the stack pointer is returned to where it was before your method was called. So deallocating everything is fast, too.
So, either way it's just an add, which takes the same amount of time regardless of the amount of data.
A smart compiler will combine several variable declarations into a single add.
When you declare a variable within a loop, in theory it could be changing the stack pointer on each iteration through the loop, but again, a smart compiler probably won't do that.
(A notable exception is C++, which does extra work because it needs to call constructors and destructors when the stack-allocated object is created or destroyed.)