How can I merge two hashes without overwritten duplicate keys in ruby?

Question

I'm new in Ruby, so, sorry if this is an easy question :)

Do you know an easy or elegant way to merge two arrays without overwriting duplicate keys?

I mean if the key is present in the original array i don't want to change anything in the original array...

Answer 1

If you have two hashes, options and defaults, and you want to merge defaults into options without overwriting existing keys, what you really want to do is the reverse: merge options into defaults:

options = defaults.merge(options)

Or, if you're using Rails you can do:

options.reverse_merge!(defaults)

Answer 2

If your problems is that the original hash and the second one both may have duplicate keys and you don't want to overwrite in either direction, you might have to go for a simple manual merge with some kind of collision check and handling:

hash2.each_key do |key|
  if ( hash1.has_key?(key) )
       hash1[ "hash2-originated-#{key}" ] = hash2[key]
  else
       hash1[key]=hash2[key]
  end
end

Obviously, this is very rudimentary and assumes that hash1 doesn't have any keys called "hash2-originated-whatever" - you may be better off just adding a number to the key so it becomes key1, key2 and so on until you hit on one that isn't already in hash1. Also, I haven't done any ruby for a few months so that's probably not syntactically correct, but you should be able to get the gist.

Alternatively redefine the value of the key as an array so that hash1[key] returns the original value from hash1 and the value from hash2. Depends what you want your outcome to be really.

Answer 3

If you really do mean array, and not hash, then:

#!/usr/bin/ruby1.8

a = [1, 2, 3, 4, 5, 6]
b = [4, 5, 6, 7, 8, 9]
c = (a + b).uniq
p c    # => [1, 2, 3, 4, 5, 6, 7, 8, 9]