Regex for getting content between $ chars from a text

Question

The problem:
I need to extract strings that are between $ characters from a block of text, but i'm a total n00b when it comes to regular expressions.

For instance from this text:
Li Europan lingues $es membres$ del sam familie. Lor $separat existentie es un$ myth.

i would like to get an array consisting of:
{'es membres', 'separat existentie es un'}

A little snippet in Python would be great.

Answer 1

The regex below captures everything between the $ characters non-greedily

\$(.*?)\$

Answer 2

You can use re.findall:

>>> re.findall(r'\$(.*?)\$', s)
['es membres', 'separat existentie es un']

Answer 3

import re;
m = re.findall('\$([^$]*)\$','Li Europan lingues $es membres$ del sam familie. Lor $separat existentie es un$ myth');

Answer 4

Valid regex demo in Perl:

my $a = 'Li Europan lingues $es membres$ del sam familie. Lor $separat existentie es un$ myth.';
my @res;
while ($a =~ /\$([^\$]+)\$/gos)
{
 push(@res, $1);
}

foreach my $item (@res)
{
 print "item: $item\n";
}

flags: s - treat all input text as single line, g - global

Answer 5

Alternative without regexes which works for this simple case:

>>> s="Li Europan lingues $es membres$ del sam familie. Lor $separat existentie es un$"
>>> s.split("$")[1::2]
['es membres', 'separat existentie es un']

Just split the string on '$' (this gives you a python list) and then only use every 'second' element of this list.

Answer 6

Import the re module, and use findall():

>>> import re
>>> p = re.compile('\$(.*?)\$')
>>> s = "apple $banana$ coconut $delicious ethereal$ funkytown"
>>> p.findall(s)
['banana', 'delicious ethereal']

The pattern p represents a dollar sign (\$), then a non-greedy match group ((...?)) which matches characters (.) of which there must be zero or more (*), followed by another dollar sign (\$).