why my code error,I would like to print the parameters of two functions.

Question

def c(*x,**y):
    print x,y
def a(*x,**y):
    print x
    def b(*x1,**y1):
        c(*(x+x1),**dict(y,**y1))
    b()

a(1,2,3,a=1,b=2)(4,5,6,c='222',d='aaa')#error

thanks

Answer 1

Replace b() with return b

Running this in Python 3.1:

def c(*x,**y):
    print(x,y)
def a(*x,**y):
    print(x)
    def b(*x1,**y1):
        c(*(x+x1),**dict(y,**y1))
    return b

a(1,2,3,a=1,b=2)(4,5,6,c='222',d='aaa')

produces:

>>> ================================ RESTART ================================
>>> 
(1, 2, 3)
(1, 2, 3, 4, 5, 6) {'a': 1, 'c': '222', 'b': 2, 'd': 'aaa'}
>>> 

Answer 2

function a() is not returning a function; actually, it returns None. Therefore, the second set of parenthesis is a call on None object - and that's an error.
Did you intend to return a function, like doing something like return b?

Answer 3

a(1,2,3,a=1,b=2)(4,5,6,c='222',d='aaa')#error

I assume you got "object is not callable" exception..

May be you need to return a function object 'b' (not result of the 'b') ?

So instead of

b()

try

return b # without braces and with 'return'

Answer 4

The error I get is:

Traceback (most recent call last):
File "./tmp.py", line 11, in a(1,2,3,a=1,b=2)(4,5,6,c='222',d='aaa') TypeError: 'NoneType' object is not callable

I can fix this by changing your code to:

#!/usr/bin/python

def c(*x,**y):
    print x,y
def a(*x,**y):
    print x
    def b(*x1,**y1):
        c(*(x+x1),**dict(y,**y1))
    return b

a(1,2,3,a=1,b=2)(4,5,6,c='222',d='aaa')

This produces the output:

(1, 2, 3)

(1, 2, 3, 4, 5, 6) {'a': 1, 'c': '222', 'b': 2, 'd': 'aaa'}

You haven't stated what you're trying to achieve though, so I don't know whether or not this is what you want.