views:

293

answers:

2

I am trying to get to the geo information off the google-picasa API. This is the original XML:

<georss:where>
  <gml:Point>
    <gml:pos>35.669998 139.770004</gml:pos>
  </gml:Point>
</georss:where>

I already have come this far, with:

$ns_geo=$item->children($namespace['georss']);
$geo=$ns_geo->children($namespace['gml']);

var_dump($geo) will output

object(SimpleXMLElement)#34 (1) { 
  ["Point"]=> object(SimpleXMLElement)#30 (1) { 
    ["pos"]=> string(18) "52.373801 4.890935" 
  } 
} 

but

echo (string)$geo->position or (string)$geo->position->pos; 

will give me nothing. Is there something obvious that i am doing wrong?

+1  A: 
echo $geo->pos[0];
Eduardo
I already try'd that also(without(string))?
Richard
+2  A: 

You could work with XPath and registerXPathNamespace():

$xml->registerXPathNamespace("georss", "http://www.georss.org/georss");
$xml->registerXPathNamespace("gml", "http://www.opengis.net/gml");
$pos = $xml->xpath("/georss:where/gml:Point/gml:pos");

From the docs, emphasis mine:

registerXPathNamespace […] Creates a prefix/ns context for the next XPath query.

More ways to handle namespaces in SimpleXML can be found here, for example:
Stuart Herbert On PHP - Using SimpleXML To Parse RSS Feeds

Tomalak
thanks, I came to the same conclusionthis worked $geo = $feed->xpath('//gml:pos');echo $geo[0];maybe the other way can't handle nested namespace elements
Richard
actually, I misspelled something.$geo->point should be $geo->Point(uppercase)
Richard