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How to pass part of url in new link? Using only HTML & PHP

Answer 1

A:

This is what urlencode does, what is the problem with the link this way?

Edit: I do not use PHP, but I think the following will do the trick (omitted the urlencode):

href="http://www.facebook.com/share.php?u=www.xxx.com/proddetail.php?&lt;?php print $_SERVER['QUERY_STRING']?>"

Dror 2010-01-12 08:35:32

i have just edited my post.i need to pass my query in to new link without having the arguments changed to %20 or anything else.

FB_noob 2010-01-12 08:38:59

Have you tried just leaving out the urlencode() function?

Kaivosukeltaja 2010-01-12 08:41:28

you mean leave the () empty?

FB_noob 2010-01-12 08:42:32

i tried urlencode() with the () empty but the new link have only the page without any query behind proddetail.php

FB_noob 2010-01-12 08:45:54

Answer 2

+3 A:

This URL:

http://www.facebook.com/share.php?u=http://www.xxx.com/proddetail.php?prod%3Dlpd026n%26cat%3D43

is only partially-encoded. You actually need to fully URL-encode it before passing to FB, so that it won't interfere with FB's URL structure. I'm sure that their script will know how to parse it properly.

The correct method is:

$url = 'http://www.facebook.com/sharer.php?u='.urlencode('http://www.xxx.com/proddetail.php?prod=lpd026n&amp;cat=43');

// evaluates to:
// http://www.facebook.com/sharer.php?u=http%3A%2F%2Fwww.xxx.com%2Fproddetail.php%3Fprod%3Dlpd026n%26cat%3D43

Update: build your dynamic query

// Original URL
$url = 'http://www.xxx.com/proddetail.php';
if ($_SERVER['QUERY_STRING'])
    $url .= '?'.$_SERVER['QUERY_STRING'];

// Final URL for FB
$fb_url = 'http://www.facebook.com/share.php?u='.urlencode($url);

K Prime 2010-01-12 08:57:55

FB_noob 2010-01-12 09:40:30

is it possible to do so?

FB_noob 2010-01-12 09:54:44

@FB_noob - Of course, just pass the final string (built from `QUERY_STRING`) to `urlencode`. See my edited post above

K Prime 2010-01-12 10:18:51

Answer 3

A:

i guess ,K Prime is right

u need to encode the whole url because the slashes and ":" are still causing problems in this link ;)

$url = 'http://www.facebook.com/sharer.php?u='.urlencode('http://www.xxx.com/proddetail.php?prod=lpd026n&cat=43');

should be fine for your purposes

Jaysn 2010-01-12 09:23:37

hi jaysn,would encode the ulr, means it only works for one page only?

FB_noob 2010-01-12 09:55:49

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How to pass part of url in new link? Using only HTML & PHP

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