How do I find the last modified file in a directory in java?
Combine these two:
- You can get the last modified time of a File using
File.lastModified()
. - To list all of the files in a directory, use
File.listFiles()
.
Note that in Java the java.io.File
object is used for both directories and files.
You can retrieve the time of the last modification using the File.lastModified() method. My suggested solution would be to implement a custom Comparator that sorts in lastModified()-order and insert all the Files in the directory in a TreeSet that sorts using this comparator.
Untested example:
SortedSet<File> modificationOrder = new TreeSet<File>(new Comparator<File>() {
public int compare(File a, File b) {
return a.lastModified() - b.lastModified();
}
});
for (File file : myDir.listFiles()) {
modificationOrder.add(file);
}
File last = modificationOrder.last();
The solution suggested by Bozho is probably faster if you only need the last file. On the other hand, this might be useful if you need to do something more complicated.
File dir = new File("/path/to/dir");
File[] files = dir.listFiles();
if (files.length == 0) {
return null;
}
File lastModifiedFile = files[0];
for (int i = 1; i < files.length; i++) {
if (lastModifiedfile.lastModified() < files[i].lastModified) {
lastModifiedFile = files[i];
}
}
You could use a Comparator
, but it is an overhead for a simple task such as this.
The comparator in Emil's solution would be cleaner this way
public int compare(File a, File b) {
if ((a.lastModified() < b.lastModified())) {
return 1;
} else if ((a.lastModified() > b.lastModified())) {
return -1;
}
return 0;
}
Casting (a.lastModified() - b.lastModified())
to int
can produce unexpected results.