Hello, I'm doing my first steps with OpenGL ES 2.0 trying things on my ipod touch. I was wondering how to solve this coordinates issue..
To explain better, I was trying to draw a quad and rotate/translate it using a vertex shader (also because from what I've read it seems the only way to do it).
Since I'm working with a ipod I have a 1.5 : 1
ratio and a viewport set by
glViewport(0, 0, backingWidth, backingHeight);
So 0,0
is the center and bounds for clipping should be at -1.0, -1.0
, -1.0, 1.0
, etc (right?)
To draw a square I had to use different values for x and y coordinates because of the aspect ratio:
static const GLfloat lineV[] = {
-0.5f, 0.33f, 0.5f, 0.33f,
0.5f, 0.33f, 0.5f,-0.33f,
0.5f,-0.33f, -0.5f,-0.33f,
-0.5f,-0.33f, -0.5f, 0.33f,
-0.5f, 0.33f, 0.5f,-0.33f,
0.5f, 0.33f, -0.5f,-0.33f,
};
It's a square with both diagonals (I know that using indexes would be more efficient but that's not the point)..
Then I tried writing a vertex shader to rotate the object while moving it:
void main()
{
m = mat4( cos(rotation), sin(rotation), 0.0, 0.0,
-sin(rotation), cos(rotation), 0.0, 0.0,
0.0, 0.0, 1.0, 0.0,
0.0, 0.0, 0.0, 1.0);
m2 = mat4(1.0);
m2[1][3] = sin(rotation)*0.8;
gl_Position = position*(m*m2);
}
It works but since coordinates are not the same the quad is distorted while it rotates. How should I prevent that? I thought if it was possible to change the view frustum to have different bounds (not -1.0 to 1.0 on both axis so that enlarging on y-axis would fix the problem).
In addition is there a better way to use matrixes? I mean, I was used to use glRotatef
without having to specify the whole matrix.. does convenience functions/constructors exist to accomplish this task?