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Answer 1

+3 A:

You need to escape the dot (.), and I'd use a + instead of * to make it at least one digit:

(\d+)\.(\d+)\.(\d+)\.(\d+)

Lucero 2010-01-18 11:14:36

I am using xmltask in ANT, so this is something I am doing by reading node value from xml file and taking the value in property<xmltask source="${act.dir.path}/pom.xml"> <regexp path="//:project/:version[1]/text()" pattern="(\d+)\.(\d+)\.(\d+)\.(\d+)" property="servlet.name"/> <regexp path="//:project/:version[1]/text()" pattern="???" property="servlet.name2"/></xmltask>Property “servlet.name” gives me first digit “5”, but how to get other values? Like “servlet.name2” should be “3”, “servlet.name3” should be “08” and “servlet.name4” should be “01” Is this possible in regexp?

saharey 2010-01-18 12:22:44

You need to specify a `replace="$1"` attribute. The `$x` inserts the text you matched (where x is the index to the group, starting with 1). Have a look at the docs! http://www.oopsconsultancy.com/software/xmltask/ for instance.

Lucero 2010-01-18 14:24:20

Answer 2

A:

language is not specified so I can suggest java solution (and I'm pretty sure that c# has similar one):

String ip = "“5.3.08.01";
String[] nums = ip.split ("."); //array of 4 elements

John Doe 2010-01-18 11:32:05

Java's `String#split(delim)` method treats `delim` as a regex, so you would need to escape the dot: `ip.split("\\.")` C# (.NET) has both a `String#Split` (which takes one or more literal delimiters in the form of a `String[]` or a `Char[]`) and a `Regex#Split` (which, like Java's `split()`, would require you to escape the dot: `@"\."`).

Alan Moore 2010-01-19 00:02:14

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split version using Regexp

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