Hi,
I'm using Python 2.6.3. When I do:
import re, urllib
f = urllib.urlopen(website)
z = f.read()
a = re.findall(r'(\b\d*\SLegos\b)[^\\/bLegos\b]', z)
print a
I get:
['/Legos', '/Legos', '525Legos', '53Legos', '11Legos', '8Legos', '10Legos', '2Legos', '0Legos', '0Legos', '0Legos', '0Legos', '9Legos', '1Legos', '0Legos', '0Legos', '0Legos', '/Legos']
If I put the website as source code into either Kodos or RegExr by gSkinner and use my above RegEx code they both say I should get:
'525Legos', '53Legos', '11Legos', '8Legos', '10Legos', '2Legos', '0Legos', '0Legos', '0Legos', '0Legos', '9Legos', '1Legos', '0Legos', '0Legos', '0Legos'
Which is much closer to the data I want.
How do I drop the '/Legos'
from returning in my Python regex?
Thanks,
Adrian