Is it possible to invoke the no modifier method in a superclass through Java reflection?
views:
313answers:
3Yes. You may need to call setAccessible(true) on the Method object before you invoke it.
Method method = getClass().getSuperclass().getDeclaredMethod("doSomething");
method.invoke(this);
if you have a bigger hierarchy, you can use:
Class current = getClass();
Method method = null;
while (current != Object.class) {
try {
method = current.getDeclaredMethod("doSomething");
break;
} catch (NoSuchMethodException ex) {
current = current.getSuperclass();
}
}
// only needed if the two classes are in different packages
method.setAccessible(true);
method.invoke(this);
(the above examples are for a method named doSomething
with no arguments. If your method has arguments, you have to add their types as arguments to the getDeclaredMethod(...)
method)
After reading the original question -- I realize I assumed you were trying to call an overridden method. Which is what I was trying to do and how I came to find this thread. Calling a base class non-overridden method should work as others here have described. However, if you are trying to call an overridden method, my answer stands as below:
I don't think calling an overridden method is possible, per
http://blogs.sun.com/sundararajan/entry/calling_overriden_superclass_method_on
Most notably:
Method.invoke
If the underlying method is an instance method, it is invoked using dynamic method lookup as documented in The Java Language Specification, Second Edition, section 15.12.4.4; in particular, overriding based on the runtime type of the target object will occur.