I inherited a table with identifiers in a format [nonnumericprefix][number]. For example (ABC123; R2D2456778; etc). I was wondering if there was a good way to split this in SQL into two fields, the largest integer formed from the right side, and the prefix, for example (ABC, 123; R2D, 2456778; etc). I know I can do this with a cursor, C# code, etc - and I will if I have to - but I don't run into things I cannot do fast and easily in SQL very often, so I thought I'd post it here.
+2
A:
You can use PATINDEX
with a pattern like '%[^0123456789]%'
or '%[^0-9]%'
to find the position of the first non-numeric character
Cade Roux
2010-01-21 15:56:09
+2
A:
- Reverse the string
- Use PATINDEX to find the first occurrence of a non numeric field
- Use the LEFT function to return the numeric portion of the string
Code sample
DECLARE @myString varchar(100);
DECLARE @largestInt int;
SET @myString = 'R2D2456778'
SET @mystring = REVERSE(@myString);
SET @largestInt = LEFT(@myString, PATINDEX('%[a-z]%', @myString) - 1)
PRINT ( CONVERT(varchar(100), @largestInt) )
Cory
2010-01-21 15:59:58
Nice solution, but to get the original int part of myString, you'll need to reverse largestInt.
rosscj2533
2010-01-21 16:08:19
This will fail with anything other thatn a-z, try R2D245.6778
astander
2010-01-21 16:24:45
+3
A:
You could try something like
DECLARE @Table TABLE(
Val VARCHAR(50)
)
INSERT INTO @Table SELECT 'ABC123'
INSERT INTO @Table SELECT 'R2D2456778'
SELECT *,
LEFT(Val,LEN(Val) - (PATINDEX('%[^0-9]%',REVERSE(Val)) - 1)),
RIGHT(Val,(PATINDEX('%[^0-9]%',REVERSE(Val)) - 1))
FROM @Table
astander
2010-01-21 16:02:33