RegExp matching string not starting with my

Question

For PMD I'd like to have a rule which warns me of those ugly variables which start with my. This means I have to accept all variables which do NOT start with my.

So, I need a RegEx (re) which behaves as follows:

re.match('myVar')       == false
re.match('manager')     == true
re.match('thisIsMyVar') == true
re.match('myOtherVar')  == false
re.match('stuff')       == true

I've tried different ones (will list them here later, sorry, no access to them right now) but haven't got it working yet.

Answer 1

^(?!my)\w+$

should work.

It first ensures that it's not possible to match my at the start of the string, and then matches alphanumeric characters until the end of the string. Whitespace anywhere in the string will cause the regex to fail. Depending on your input you might want to either strip whitespace in the front and back of the string before passing it to the regex, or use add optional whitespace matchers to the regex like ^\s*(?!my)(\w+)\s*$. In this case, backreference 1 will contain the name of the variable.

And if you need to ensure that your variable name starts with a certain group of characters, say [A-Za-z_], use

^(?!my)[A-Za-z_]\w*$

Note the change from + to *.

Answer 2

How about this

/^(my).*/

Answer 3

/^(?!my).*/

(?!expression) is a negative lookahead; it matches a position where expression doesn't match starting at that position.

Answer 4

i would simply use, if not var.startswith("my"): accept_it()

Answer 5

You could either use a lookahead assertion like others have suggested. Or, if you just want to use basic regular expression syntax:

^(.?$|[^m].+|m[^y].*)

This matches strings that are either zero or one characters long (^.?$) and thus can not be my. Or strings with two or more characters where when the first character is not an m any more characters may follow (^[^m].+); or if the first character is a m it must not be followed by a y (^m[^y]).