$arr = array('id1','id2',...);
How to get #id1,#id2,.. from the above array?
views:
71answers:
3
+2
A:
$arr[0];
$arr[1];
The code you just provided is the same as
$arr = array(
0 => "id1",
1 => "id2");
In order to make a list of ids in CSS
$string = '';
foreach($arr as $id)
{
$string .= "#" . $id . " ";
}
Chacha102
2010-01-24 05:40:47
+1 for covering both possible interpretations of an ambiguous question.
zombat
2010-01-24 05:45:44
Yeah, read it wrong the first time. Thought he was asking how to access them period.
Chacha102
2010-01-24 05:46:42
Just because he used id1 and id2 doesn't mean every ID will begin with id and end with a number, those are just examples. They could be IDs such as 'harp1', 'mem1', and 'gut2', completely irrelevant of each other.
animuson
2010-01-24 06:01:43
+4
A:
$arr = array('id1', 'id2', ...);
$ids = '#' . join(',#', $arr);
echo $ids; // => #id1,#id2,...
Jordan
2010-01-24 05:43:05
@Alix True. I always use `implode` though because it parallels `explode`. Since `split` is deprecated, it seems weird to me to use `join` and `explode` together.
Doug Neiner
2010-01-24 05:52:08
Oh, fair enough. For some reason I thought that since 'split' is deprecated then so is 'join,' but I that was silly of me. I've updated my answer, thanks.
Jordan
2010-01-24 05:52:25
@Jordan: I always use `implode()` too, I was just adding an emphasis on Doug comment. =)
Alix Axel
2010-01-24 05:53:27
Right, but I prefer join myself. It just makes more sense in my brain. "implode" seems like such a violent verb. I guess my approach to programming is a bit synaesthetic at times.
Jordan
2010-01-24 05:55:27
+1
A:
you can iterate the array
foreach ($arr as $k){
print "#".$k."\n";
}
each "$k" is your array items
ghostdog74
2010-01-24 05:43:49