I want to transform a date from this format: 01/07/09 to this jan 07,09.
How can I do that in PHP?
views:
60answers:
2
+2
A:
Use strptime to parse the value you've got, then date to output it in the format you want:
echo date("M d,y", strptime("01/07/09", "d/m/y"));
If you're on Windows, or using a version of PHP where strptime is not available (< PHP 5.1.0), then use strtotime instead, but be careful to make sure your date is in a US English format (i.e. "01/07/09" means January 7th 2009, not 1st July 2009).
Also, if you really want jan, rather than Jan, then use strtolower:
echo strtolower(date("M d,y", strptime("01/07/09", "d/m/y"));
Dominic Rodger
2010-01-25 06:30:00
Also note, `strptime` is not implemented on Windows.
Brian McKenna
2010-01-25 06:33:10
@Brian, thanks - edited in a comment about using `strtotime` where `strptime` is unavailable.
Dominic Rodger
2010-01-25 06:36:20
@Dominic, you have the order of arguments for `date` mixed up. Should be: `date( $format, [ $timestamp ] )`
fireeyedboy
2010-01-25 06:49:49
@fireeyedboy - thanks, fixed. I suck.
Dominic Rodger
2010-01-25 09:00:28
+6
A:
I'm pretty sure this is what you need.
<?php echo date('M d, y', strtotime('01/07/09'));?>
Thorpe Obazee
2010-01-25 06:31:06