views:

1035

answers:

2

I'm building a form where I need multiple optional inputs, what I have is basically this:

form example

Every time a user presses the plus button a new row of form inputs should be added to the form, how can I do this in jQuery? Also, is it possible to automatically add a new row when all rows (or just the last row, if it's easier / faster) are filled? That way the user wouldn't need to press the plus button.

I'm sorry for asking maybe such a basic question but I'm still very green with jQuery, I could do this with PHP but I'm sure Javascript / jQuery plays a more appropriate role here.

Thanks in advance!


@alex:

<!DOCTYPE html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.0/jquery.min.js"&gt;&lt;/script&gt;
<script type="text/javascript">
$form = $('#personas');
$rows = $form.find('.person');

$('a#add').click(function() {
    $rows.find(':first').clone().insertAfter($rows.find(':last'));
    $justInserted = $rows.find(':last');
    $justInserted.hide();
    $justInserted.find('input').val(''); // it may copy values from first one
    $justInserted.slideDown(500);
});
</script>
</head>

<body>
<form id="personas" name="personas" method="post" action="">
  <table width="300" border="1" cellspacing="0" cellpadding="2">
    <tr>
      <td>Name</td>
      <td>More?</td>
    </tr>
    <tr class="person">
      <td><input type="text" name="name[]" id="name[]" /></td>
      <td><a href="#" id="add">+</a></td>
    </tr>
  </table>
</form>
</body>
</html>
+1  A: 

Untested. Modify to suit:

$form = $('#my-form');

$rows = $form.find('.person-input-row');

$('button#add-new').click(function() {

    $rows.find(':first').clone().insertAfter($rows.find(':last'));

    $justInserted = $rows.find(':last');
    $justInserted.hide();
    $justInserted.find('input').val(''); // it may copy values from first one
    $justInserted.slideDown(500);


});

This is better than copying innerHTML because you will lose all attached events etc.

alex
Thanks. That makes sense but I still can't get it to work, check my edited question.
Alix Axel
This will clone what is inside the tr, in this case the td's and insert td's after the last one. close but not quite right.
Rippo
It was alright up until the edit :) Sorry, I went out after posting and didn't have a chance to make edits.
alex
+2  A: 

This will get you close, the add button has been removed out of the table so you might want to consider this...

<script type="text/javascript">
    $(document).ready(function() {
        $("#add").click(function() {
          $('#mytable tbody>tr:last').clone(true).insertAfter('#mytable tbody>tr:last');
          return false;
        });
    });
</script>

HTML markup looks like this

  <a  id="add">+</a></td>
  <table id="mytable" width="300" border="1" cellspacing="0" cellpadding="2">
  <tbody>
    <tr>
      <td>Name</td>
    </tr>
    <tr class="person">
      <td><input type="text" name="name" id="name" /></td>
    </tr>
    </tbody>
  </table>

EDIT To empty a value of a textbox after insert..

    $('#mytable tbody>tr:last').clone(true).insertAfter('#mytable tbody>tr:last');
    $('#mytable tbody>tr:last #name').val('');
    return false;

EDIT2 Couldn't help myself, to reset all dropdown lists in the inserted TR you can do this

$("#mytable tbody>tr:last").each(function() {this.reset();});           

I will leave the rest to you!

Rippo
That works fine, thanks. Now, is there any way to reset all inputs / selects / textareas / etc to their original state in the newly created row?
Alix Axel