I can't figure this out:
22.584\r\n\t\t\tl-6.579-22
I want to match the "\r\n\t\t\t" and replace with a single space " ". Problem is the number of "\t", "\r", and "\n" fluctuates, as do the surrounding characters.
Help!
views:
101answers:
6Nope. Doesn't work.
neezer
2010-01-27 09:32:43
@neezer, note that `\s` matches more than just `\t`, `\r` or `\n`. It matches (in most cases) these: `[ \t\n\x0B\f\r]`, but that may be fine with you of course.
Bart Kiers
2010-01-27 09:32:48
@neezer: What language are you using?
KennyTM
2010-01-27 09:33:52
@neezer: In what way doesn't it work? Does it give an error? Does it replace too much? Too little? Does it do nothing at all?
Mark Byers
2010-01-27 09:34:11
I'm using Ruby. It doesn't match anything. The values in the string in my question are not escape values (as in, to match, you'd search for `\\r` or the like).
neezer
2010-01-27 09:35:46
@neezer: See update (I didn't translate it to Ruby.)
KennyTM
2010-01-27 09:37:05
Your edit matches them individually, not the group. I need to replace the whole group with a single space. Any other thoughts?
neezer
2010-01-27 09:37:09
Whoops... nevermind. For the "+". That works.
neezer
2010-01-27 09:37:39
I think this is the correct idiom for replacing a sequence of whitespace characters with a space. It matches all possible whitespace, not just \r, \t and \n, it matched a sequence of one or more, and it does a global replace rather than just replacing the first such sequence. The only tricky bit is making the regexp apply to the whole string rather than one line at a time, otherwise you get left with \n's in your input.
liwp
2010-01-27 09:43:20
When I answered there was no mention of ruby, or any other language. The post was edited later, as you can see. Also, accepted answer uses Perl's syntax.
kemp
2010-01-27 16:50:17
A:
#!/usr/bin/ruby1.8
s = "22.584\r\n\t\t\tl-6.579-22"
p s # => "22.584\r\n\t\t\tl-6.579-22"
p s.gsub(/[\r\n\t]+/, ' ') # => "22.584 l-6.579-22"
Wayne Conrad
2010-01-27 13:26:37
A:
I'd treat the CR-NL as one atom:
str.gsub!(/(?:\r\n)+\t+/, ' ')
glenn jackman
2010-01-27 16:50:01