views:

298

answers:

7

Hey all,

I have need of a sort of specialized dictionary. My use case is this: The user wants to specify ranges of values (the range could be a single point as well) and assign a value to a particular range. We then want to perform a lookup using a single value as a key. If this single value occurs within one of the ranges then we will return the value associated to the range.

For example:

// represents the keyed value
struct Interval
{
    public int Min;
    public int Max;
}

// some code elsewhere in the program
var dictionary = new Dictionary<Interval, double>();
dictionary.Add(new Interval { Min = 0, Max = 10 }, 9.0);
var result = dictionary[1];
if (result == 9.0) JumpForJoy();

This is obviously just some code to illustrate what I'm looking for. Does anyone know of an algorithm to implement such a thing? If so could they point me towards it, please?

I have already tried implementing a custom IEqualityComparer object and overloading Equals() and GetHashCode() on Interval but to no avail so far. It may be that I'm doing something wrong though.

+6  A: 

This is only going to work when the intervals don't overlap. And your main problem seems to be converting from a single (key) value to an interval.

I would write a wrapper around SortedList. The SortedList.Keys.IndexOf() would find you an index that can be used to verify if the interval is valid and then use it.

Henk Holterman
I just tried it by using a standard SortedList with a custom comparer (that checks to see if the intervals intersect or not. It's working well!
Jeffrey Cameron
Indeed, if the intervals are required to not overlap then the problem is trivial; you can just binary search a sorted list. If the intervals are allowed to overlap then you have a rather more difficult problem.
Eric Lippert
+1  A: 

This isn't exactly what you want but I think it may be the closest you can expect.

You can of course do better than this (Was I drinking earlier?). But you have to admit it is nice and simple.

var map = new Dictionary<Func<double, bool>, double>()
{
    { d => d >= 0.0 && d <= 10.0, 9.0 }
};

var key = map.Keys.Single(test => test(1.0))
var value = map[key];
ChaosPandion
intriguing, I hadn't thought of using a function as a key ... ! The point of my using Dictionary was to have O(1) lookup though since this table will be queried many times. Is there any way to make the lookup quicker?
Jeffrey Cameron
This is O(n) in lookups. You can do way better than that.
Eric Lippert
@Eric - Eventually the embarrassment kind of blends together. :)
ChaosPandion
A: 

You could check out the powercollections here found on codeplex that has a collection that can do what you are looking for.

Hope this helps, Best regards, Tom.

tommieb75
What collection type would that be?
Jørn Schou-Rode
@Jorn Schou-Rode: MultiDictionary, 'MultiDictionary class that associates values with a key. Unlike an Dictionary, each key can have multiple values associated with it. When indexing an MultiDictionary, instead of a single value associated with a key, you retrieve an enumeration of values.'
tommieb75
That makes no sense as the OP wants to map an interval of values to one single value. So the it's the key that needs to consist of multiple values, ether the interval boundaries or all values in that interval.
Frank Bollack
@Frank: As per the documentation, 'MultiDictionary<TKey, TValue>', and 'When constructed, you can chose to allow the same value to be associated with a key multiple times, or only one time.', and that one of the methods was 'AddMany' which implies 'Adds new values to be associated with a key. If duplicate values are permitted, this method always adds new key-value pairs to the dictionary. If duplicate values are not permitted, and key already has a value equal to one of values associated with it, then that value is replaced, and the number of values associate with key is unchanged.'
tommieb75
A multi dictionary is not an appropriate data structure to represent an interval tree.
Eric Lippert
+1  A: 

I have solved a similar problem by ensuring that the collection is contiguous where the intervals never overlap and never have gaps between them. Each interval is defined as a lower boundary and any value lies in that interval if it is equal to or greater than that boundary and less than the lower boundary of the next interval. Anything below the lowest boundary is a special case bin.

This simplifies the problem somewhat. We also then optimized key searches by implementing a binary chop. I can't share the code, unfortunately.

Jeff Yates
A: 

I would make a little Interval class, which would something like that:

public class Interval
{
    public int Start {get; set;}
    public int End {get; set;}
    public int Step {get; set;}
    public double Value {get; set;}

    public WriteToDictionary(Dictionary<int, double> dict)
    {
        for(int i = Start; i < End; i += Step)
        {
            dict.Add(i, Value);
        }
    }
}

So you still can a normal lookup within your dictionary. Maybe you should also perform some checks before calling Add() or implement some kind of rollback if any value is already within the dictionary.

Oliver
+10  A: 

A dictionary is not the appropriate data structure for the operations you are describing.

If the intervals are required to never overlap then you can just build a sorted list of intervals and binary search it.

If the intervals can overlap then you have a more difficult problem to solve. To solve that problem efficiently you'll want to build an interval tree:

http://en.wikipedia.org/wiki/Interval_tree

This is a well-known data structure. See "Introduction To Algorithms" or any other decent undergraduate text on data structures.

Eric Lippert
The intervals are not allowed to overlap in my simulation so I'll stick to the SortedList. thanks for the advice Eric!
Jeffrey Cameron
A: 

You can find a Java flavored C# implementation of an interval tree in the Open Geospatial Library. It needs some minor tweaks to solve your problem and it could also really use some C#-ification.

It's Open Source but I don't know under what license.

Jonas Elfström