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184

answers:

6

Is it possible, from .NET, to mimic the exact randomization that Java uses? I have a seed, and I would like to be able to recieve the same results in both C# and Java when creating a random number.

+4  A: 

If you have the source code of the java.util.Random class for your Java implementation, you can easily port it to .NET.

If you require both applications (Java and .NET) to use a certain random number generator, you'd better implement one in both platforms and use it instead, as the system provided version might change its behavior as a result of an update.(Looks like the Java specification precisely describes the behavior of its PRNG.)

Mehrdad Afshari
But isn't the algorithm an implementation detail and likely to change between versions/implementations? IMO it would be better to implement a custom algorithm both in Java and C# to get consistent results.
dtb
@dtb: Was thinking about the same thing. If it's going to be temporary, for testing purposes, that would suffice. Otherwise, yes, you should implement your own.
Mehrdad Afshari
@dtb: The algorithm is specified in the documentation of Java's Random class and therefore a specification. Implementation details may change but I highly doubt that the actual sequence generated by it would in a future version. If at all, they're more likely to add a different PRNG in a separate class. But given Java's intended scope and mature libraries out there that actually do a good job for pseudo-random number generation, I doubt that will happen anyway.
Joey
The API doc of java.util.Random actually specifies the exact algorithm: http://java.sun.com/javase/6/docs/api/java/util/Random.html#next(int) - not sure whether that is mandated by the official Java compatibility testsuite, though.
Michael Borgwardt
I'm going to go ahead and give this a shot, thanks!
George
A: 

Well, you can look in the source code for Random.java and copy the algorithm, constants, etc.etc, but Random uses System.nanoTime in its constructor so you won't get the same results.

From java.util.Random

public Random() { this(++seedUniquifier + System.nanoTime()); }

I wouldn't be at all surprised if the source in C# would show you something similar.

Edit: Disregard, as has been pointed out, the constructor that takes an input seed never accesses time.

Steve B.
He's using the same seed for both, so the default seed in the Java implementation is irrelevant.
Will Vousden
^^ What he said.
Svish
It only uses it if you don't have a seed, there are 2 constructors `Random()` - Takes nothing and uses `Environment.TickCount` and `Random(int32 num)` that takes your seed instead of the TickCount.
Nick Craver
A: 

Maybe it would make sense to implement your own simple pseudo-random number generator? That way you have complete control and can garauntee the same seed gives the same results in both environments. Probably a bit more work than porting one to the other though.

FrustratedWithFormsDesigner
+1  A: 

If you don't need a cryptographically secure pseudorandom number generator then I would go for the Mersenne twister. You can find source code for C# here and Java here.

Jonas Elfström
That wasn't the question, though. And `java.util.Random` isn't crypographically secure either so that's obviously not h(is|er) concern ;-)
Joey
It wasn't the question but since *"mimic the exact randomization that Java uses"* seems hard to impossible to do I focused on *"I would like to be able to recieve the same results in both C# and Java"* instead.
Jonas Elfström
A: 

Another option might be to write your random numbers out to a file once from one platform and then just load your random numbers for both platforms from that file, or you could load them from a service such as random.org

jk
+1  A: 

You don't need to read the source code. The formula is a one-liner and is given in the documentation for java.util.Random.

Here's a partial translation:

[Serializable]
public class Random
{
    public Random(UInt64 seed)
    {
        this.seed = (seed ^ 0x5DEECE66DUL) & ((1UL << 48) - 1);
    }

    public int NextInt(int n)
    {
        if (n <= 0) throw new ArgumentException("n must be positive");

        if ((n & -n) == n)  // i.e., n is a power of 2
            return (int)((n * (long)Next(31)) >> 31);

        long bits, val;
        do
        {
            bits = Next(31);
            val = bits % (UInt32) n;
        }
        while (bits - val + (n - 1) < 0);

        return (int) val;
    }

    protected UInt32 Next(int bits)
    {
        seed = (seed * 0x5DEECE66DL + 0xBL) & ((1L << 48) - 1);

        return (UInt32)(seed >> (48 - bits));
    }

    private UInt64 seed;
}

Example:

Random rnd = new Random(42);
Console.WriteLine(rnd.NextInt(10));
Console.WriteLine(rnd.NextInt(20));
Console.WriteLine(rnd.NextInt(30));
Console.WriteLine(rnd.NextInt(40));
Console.WriteLine(rnd.NextInt(50));

Output on both platforms is 0, 3, 18, 4, 20.

finnw