For homework, I was given the following 8 code fragments to analyze and give a Big-Oh notation for the running time. Can anybody please tell me if I'm on the right track?
//Fragment 1
for(int i = 0; i < n; i++)
sum++;
I'm thinking O(N) for fragment 1
//Fragment 2
for(int i = 0; i < n; i+=2)
sum++;
O(N) for fragment 2 as well
//Fragment 3
for(int i = 0; i < n; i++)
for( int j = 0; j < n; j++)
sum++;
O(N^2) for fragment 3
//Fragment 4
for(int i = 0; i < n; i+=2)
sum++;
for(int j = 0; j < n; j++)
sum++;
O(N) for fragment 4
//Fragment 5
for(int i = 0; i < n; i++)
for( int j = 0; j < n * n; j++)
sum++;
O(N^2) for fragment 5 but the n * n is throwing me off a bit so I'm not quite sure
//Fragment 6
for(int i = 0; i < n; i++)
for( int j = 0; j < i; j++)
sum++;
O(N^2) for fragment 6 as well
//Fragment 7
for(int i = 0; i < n; i++)
for( int j = 0; j < n * n; j++)
for(int k = 0; k < j; k++)
sum++;
O(N^3) for fragment 7 but once again the n * n is throwing me off
//Fragment 8
for(int i = 1; i < n; i = i * 2)
sum++;
O(N) for fragment 8