Include (../x.php) doesn't work on my Linux server why?

Question

In my Xampp I can do :

require_once('../myFile.php');

And it works.

When I upload the file that do the require_once, it doesn't work.

Here is the error on the server:

Warning: require_once(../myFile.php) [function.require-once]: failed to open stream: No such file or directory in /home/xxx/public_html/yyyy/testinclude.php on line 11

Fatal error: require_once() [function.require]: Failed opening required '../myFile.php' (include_path='.:/usr/lib/php:/usr/local/lib/php') in /home/xxx/public_html/yyyy/testinclude.php on line 11

Any idea?

Answer 1

If myFile.php doesn't exist in directory public_html, then it won't work.

If you want it to look in the same directory as you, try require_once('./myFile.php')

Answer 2

One possible reason why its not working is that your file-casing isn't exactly the same.

In UNIX, file paths are case-sensitive. This is not the case in WIN. So, if you are including ../myFile.php, your file must be name myFile.php, not myfile.php.

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Also, include are always including files according to the current path. Consider these two files.

/home/xxx/public_html/first.php

<?php include('dir/second.php'); ?>

/home/xxx/public_html/dir/second.php

<?php include('third.php'); ?>

When running first.php, the second file will include /home/xxx/public_html/third.php.

When running dir/second.php directly, it will include /home/xxx/public_html/dir/third.php.

If your include must always be relative to the current file, use the following:

include(dirname(__FILE__) . '/third.php');

Using the above code fragment, dir/second.php will always include /home/xxx/public_html/dir/third.php regardless of the current directory.

Answer 3

Where is your myFile.php file relative to your testinclude.php file?

If you're requiring it in ../ then myFile.php needs to be one level higher than testinclude.php (i.e. in /home/xxx/public_html/)