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Using values inside a function out side

Answer 1

+2 A:

you put a return statement in your function. then you can use it "outside"

ghostdog74 2010-02-02 15:24:06

Answer 2

A:

Not without making each of the function variables global

function func() {
  global $var1, $var2, ...;
  ...
}
?>
<td><?=$var1?></td>

Note: for the above to work, short tags must be enabled, otherwise you have to do <?php echo $var1 ?>

Tor Valamo 2010-02-02 15:24:52

Answer 3

A:

You need to return the value out of the function:

function foo() {
  return array("bar");
}

Any time I call foo(), I'll be able to catch it's return value:

$items = foo(); // $items is now array("bar");

foreach($items as $item) {
  print "<td>" . $item . "</td>"; // <td>bar</td>
}

Jonathan Sampson 2010-02-02 15:25:36

Answer 4

A:

There are three ways:

1., Either you save result of each loop turnaround into an array and then loop through array

<table>
<?php foreach ($array as $a){
echo "<tr><td>$a</td></tr>";
} ?>
</table>

2., or you echo each row through the loop (in that off function)

3., or you start a buffer with ob_start and then save it to some variable ($result = ob_get_contents())

Either way, you'll need more loops and some echos.

Adam Kiss 2010-02-02 15:26:08

Answer 5

+2 A:

Yes, you can get the result of a function and use it outside. Example:

function addSomething($a, $b)
{
    $sum = $a + $b;
    return $sum;
}

$mySum = addSomething(15, 45);

print $mySum;  // Will show 60

You can only 'return' one variable as it will 'exit' the function once you return. If you need more data than just a single variable you can return an array and pick that up on the other side.

angryCodeMonkey 2010-02-02 15:27:54

Answer 6

+2 A:

Tatu Ulmanen 2010-02-02 15:28:36

Why the downvote? This is exactly what the OP asked for, with an clear example.

Tatu Ulmanen 2010-02-02 15:33:05

Thank you very much :D

LiveEn 2010-02-02 16:52:47

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Using values inside a function out side

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