how to remove all instances of an element from a list in python

Question

lets say I have a=[[1,1],[2,2],[1,1],[3,3],[1,1]] is there a function that remove all instances of [1,1]

thanks

Answer 1

Use a list comprehension:

[x for x in a if x != [1, 1]]

Answer 2

If you want to modify the list in-place,

a[:] = [x for x in a if x != [1, 1]]

Answer 3

new_list = filter(lambda x: x != [1,1], a)

Or as a function:

def remove_all(element, list):
    return filter(lambda x: x != element, list)

a = remove([1,1],a)

Or more general:

def remove_all(elements, list):
    return filter(lambda x: x not in elements, list)

a = remove(([1,1],),a)

Answer 4

def remAll(L, item):
    answer = []
    for i in L:
        if i!=item:
            answer.append(i)
    return answer

Answer 5

Google finds Delete all items in the list, which includes gems such as

from functools import partial
from operator import ne
a = filter(partial(ne, [1, 1]), a)

Answer 6

filter([1,1].__ne__,a)