Can you please help me solve my Java programming exercise?

Question

We are having a party with amounts of tea and candy. Return the int outcome of the party encoded as 0=bad, 1=good, or 2=great. A party is good (1) if both tea and candy are at least 5. However, if either tea or candy is at least double the amount of the other one, the party is great (2). However, in all cases, if either tea or candy is less than 5, the party is always bad (0).

teaParty(6, 8) → 1 teaParty(3, 8) → 0 teaParty(20, 6) → 2

public int teaParty(int tea, int candy) 
{
    if ( teaandcandy >=5) return "2";
    if ( teanandcandy <= 5) return "0"; 
} 

Answer 1

I guess you have to write a method teaParty like this:

int teaParty( int teaValue, int candyValue ) {
    int result = ....
    // enter the given conditions and calculations here
    return result;
}

Answer 2

The question is asking you to write a Java method that ranks how good a party is.

It ranks the party based on 2 things, that ammount of candy, and the amount of tea.

The rank is determined by 2 rules:

1. If there is less that 5 candy or less than 5 tea, the party was bad (0)
2. If there is at least twice as much of one of the two things (candy or tea) then the party was great (2)
3. In all other cases, the party was just good (1)

Here is the implementation:

// This method will tell you how good the party was
// based on some pre defined rules
public int teaParty(int tea, int candy){
    // first rule, if they is less that 5 candy or tea
    // the party is bad (0)
    if (tea < 5 || candy < 5) return 0;
    // second rule, if there is twice as much tea as candy
    // or there is twice as much candy as tea, great party (2)
    if (tea >= 2 * candy) return 2;
    if (candy >= 2 * tea) return 2;
    // otherwise, the party was just good
    return 1;
}

Implementation that uses else and only returns from one point in the method:

// This method will tell you how good the party was
// based on some pre defined rules
public int teaParty(int tea, int candy){
    int score = -1;
    // first rule, if they is less that 5 candy or tea
    // the party is bad (0)
    if (tea < 5 || candy < 5) {
        score = 0; 
    }
    // second rule, if there is twice as much tea as candy
    // or there is twice as much candy as tea, great party (2)
    else if (tea >= 2 * candy) {
        score = 2;
    }
    else if (candy >= 2 * tea) {
        score = 2;
    }
    else {
    // otherwise, the party was just good
        score = 1;
    }
    return score;
}

Answer 3

int greatnessOfParty(int teaAmount, int candyAmount)  
{  
  //evaluate condition for a bad party  
  //evaluate condition for good party   
  // else return 2
}

The third condition does not need to be evaulated because if it gets to that point you know it must be true. Without giving the answer directly this should help.