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172

answers:

2

Here are the details for what Picasa stores as a hash. It stores them like this:

faces=rect64(54391dc9b6a76c2b),4cd643f64b715489
[DSC_2289.jpg]
faces=rect64(1680000a5c26c82),76bc8d8d518750bc

Info on the web says this:

The number encased in rect64() is a 64-bit hexadecimal number.

  • Break that up into four 16-bit numbers.
  • Divide each by the maximum unsigned 16-bit number (65535) and you'll have four numbers between 0 and 1.
  • The four numbers remaining give you relative coordinates for the face rectangle: (left, top, right, bottom).
  • If you want to end up with absolute coordinates, multiple the left and right by the image width and the top and bottom by the image height.

So my code to turn that into a RectangleF works just fine (only keeping relative coordinates):

    public static RectangleF GetRectangle(string hashstr)
    {
        UInt64 hash = UInt64.Parse(hashstr, System.Globalization.NumberStyles.HexNumber);
        byte[] bytes = BitConverter.GetBytes(hash);

        UInt16 l16 = BitConverter.ToUInt16(bytes, 6);
        UInt16 t16 = BitConverter.ToUInt16(bytes, 4);
        UInt16 r16 = BitConverter.ToUInt16(bytes, 2);
        UInt16 b16 = BitConverter.ToUInt16(bytes, 0);

        float left = l16 / 65535.0F;
        float top = t16 / 65535.0F;
        float right = r16 / 65535.0F;
        float bottom = b16 / 65535.0F;

        return new RectangleF(left, top, right - left, bottom - top);
    }

Now I have a RectangleF and I want to turn it back into the hash mentioned above. I can't seem to figure this out. It looks like picasa uses 2 bytes including precision, however a float in C# is 8 bytes, and even BitConverter.ToSingle is 4 bytes.

Any help appreciated.

EDIT: Here is what I have right now

    public static string HashFromRectangle(RectangleCoordinates rect)
    {
        Console.WriteLine("{0} {1} {2} {3}", rect.Left, rect.Top, rect.Right, rect.Bottom);
        UInt16 left = Convert.ToUInt16((float)rect.Left * 65535.0F);
        UInt16 top = Convert.ToUInt16((float)rect.Top * 65535.0F);
        UInt16 right = Convert.ToUInt16((float)rect.Right * 65535.0F);
        UInt16 bottom = Convert.ToUInt16((float)rect.Bottom * 65535.0F);            

        byte[] lb = BitConverter.GetBytes(left);
        byte[] tb = BitConverter.GetBytes(top);
        byte[] rb = BitConverter.GetBytes(right);
        byte[] bb = BitConverter.GetBytes(bottom);

        byte[] barray = new byte[8];
        barray[0] = lb[0];
        barray[1] = lb[1];
        barray[2] = tb[0];
        barray[3] = tb[1];
        barray[4] = rb[0];
        barray[5] = rb[1];
        barray[6] = bb[0];
        barray[7] = bb[1];

        return BitConverter.ToString(barray).Replace("-", "").ToLower();
    }
A: 

Dear Sir,

It looks like you need to take out the float types from HashFromRectangle(rect) like so:

    UInt16 left = (UInt16)( rect.Left * 65535.0F);
    UInt16 top =(UInt16) (rect.Top * 65535.0F);
    UInt16 right = (UInt16) (rect.Right * 65535.0F);
    UInt16 bottom = (UInt16) (rect.Bottom * 65535.0F);

Also, it might be more readable to use this for filling in the array:

    Array.Copy(lb, 0, barray, 0, 2);
    Array.Copy(tb, 0, barray, 2, 2);
    Array.Copy(rb, 0, barray, 4, 2);
    Array.Copy(bb, 0, barray, 6, 2);

Let me know if this works!

Aaron

Limited Atonement
Unfortunately not. I tested this on a known hash of 1cf0102160008916. It turns out the hash ff2983393f520976 and reverses to the wrong coordinates.
esac
A: 

Your current code is swapping the bytes of each coordinate. This is because BitConverter gives you the bytes in little endian order (i.e. the first byte in the array is the least significant byte). Swapping around your assignments as follows makes decoding and re-encoding give back the original hash.

        barray[0] = lb[1];
        barray[1] = lb[0];
        barray[2] = tb[1];
        barray[3] = tb[0];
        barray[4] = rb[1];
        barray[5] = rb[0];
        barray[6] = bb[1];
        barray[7] = bb[0];

That said, I think it's clearer to do the conversion using simple multiplies and adds. You can do a similar thing with the decoding of the hash string if you read it in as a single ulong and subtract/divide. e.g. for the encoding:

    public static ushort ToUShort(double coordinate)
    {
        double ratio = Math.Max(0, Math.Min(Math.Round(coordinate * 65535), 65535));
        return (ushort)ratio;
    }

    public static string HashFromRectangle(Rect rect)
    {
        ulong left = ToUShort(rect.Left);
        ulong top = ToUShort(rect.Top);
        ulong right = ToUShort(rect.Right);
        ulong bottom = ToUShort(rect.Bottom);

        ulong hash = (((left * 65536) + top) * 65536 + right) * 65536 + bottom;
        return hash.ToString("x");
    }
Dave
Thanks, it seems to lose a little precision, but this does it correctly.
esac