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Java/JSP How to get domain URL + web application name?

Answer 1

+4 A:

I would strongly suggest you to read through the docs, for similar methods. If you are interested in context path, have a look here, ServletContext.getContextPath().

Adeel Ansari 2010-02-05 03:43:20

Answer 2

A:

Take a look at the documentation for HttpServletRequest.
In order to build the URL in your example you will need to use:

getScheme()
getServerName()
getServerPort()
getContextPath()

Here is a method that will return your example:

public static String getURLWithContextPath(HttpServletRequest request)
{
   return request.getScheme() + "://" + request.getServerName() + request.getServerPort() + request.getContextPath();
}

Jataro 2010-02-05 04:15:05

Answer 3

+3 A:

The web application name (actually the context path) is available by HttpServletrequest#getContextPath() (and thus NOT getServletPath() as one suggested before). You can retrieve this in JSP by ${pageContext.request.contextPath}.

If you intend to use this for all relative paths in your JSP page (which would make this question more sense), then you can make use of the HTML <base> tag:

<!doctype html>
<html lang="en">
    <head>
        <title>SO question 2204870</title>
        <base href="${pageContext.request.contextPath}">
        <script src="js/global.js"></script>
        <link rel="stylesheet" href="css/global.css">
    </head>
    <body>
        <ul>
            <li><a href="home.jsp">Home</a></li>
            <li><a href="faq.jsp">FAQ</a></li>
            <li><a href="contact.jsp">Contact</a></li>
        </ul>
    </body>
</html>

All links in the page will then automagically be relative to the <base> so that you don't need to copypaste the context path everywhere. Note that when relative links start with a /, then they will not be relative to the <base> anymore, but to the domain root instead.

BalusC 2010-02-05 11:36:28

Doc states, "The context path returned by `ServletContext.getContextPath()` should be considered as the prime or preferred context path of the application". That was the reason I included this one to my original answer, after realizing the thing. I didn't remove my first attempt, as I want the OP to consider reading through the docs and know a little more about related methods. I hope you are getting my point.

Adeel Ansari 2010-02-05 14:02:47

@Vinegar: For JSP files, the `getServletPath()` returns `/filename.jsp`. The OP wasn't asking for that at all, this is certainly not the way to go.

BalusC 2010-02-05 14:25:52

I would certainly make correction in my post, but this time I was expecting the response to my comment, which is entirely different :).

Adeel Ansari 2010-02-08 09:44:33

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