Hello,
I'm posting simple version of php and Jquery code of the page that I need to create. As you can see, this example contains PHP break functions, and the name of this page is test.php.
The problem is, when I try to open the first part of this page (case 1) Jquery load function successfully is started and successfully load case 2 in the same DIV the second Jquery code for alert message. But if FireFox and Chrome that alert message it would not show up. Why?
Thx.
The code of the compleate page is:
<?php
include_once '../include/config.inc.php';
include_once '../include/options.inc.php';
include_once '../include/security.inc.php';
include_once '../include/functions.inc.php';
include_once '../templates/config.php';
?>
<script type="text/javascript" src="jquery/jquery-1.3.2.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$("#one").live("click", function(){
$("#xuy").load("test.php?x=2");
});
});
</script>
<script type="text/javascript">
$(document).ready(function() {
$('#test').click(function() {
alert("test for alert message");
});
});
</script>
<style>
#xuy{ width:770px; height:230px; border:1px solid #999; background-color:#33FF00;}
#one{ border:1px solid #F00; width:555px; background-color:#FFFF00;}
#two{ border:1px solid #000; width:355px; background-color:#CCCCCC;}
#three{ border:1px solid #ccc; width:255px; background-color: #00FFFF;}
</style>
<?
if (!isset($x)) $x = '';
switch ($x)
{
default:
case 1:
?>
<div id="xuy"><div id="one">DIV one</div></div>
<?
break;
case 2:
?>
<div id="two">DIV two</div><br>
<div id="test">click for Jquery alert</div>
<?
}
?>