HttpServletRequest to complete URL

Question

I have an HttpServletRequest object.

How do I get the complete and exact URL that cause this call to arrive at my servlet?

Or at least as accurately as possible, as there are perhaps things that can be regenerated (the order of the parameters, perhaps).

Answer 1

HttpServletRequest

getRequestURL() - Reconstructs the URL the client used to make the request.

getQueryString() - Returns the query string that is contained in the request URL after the path.

E.g.

String fullURL = request.getRequestURL().append("?" + 
     request.getQueryString()).toString();

Answer 2

Combining the results of getRequestURL() and getQueryString() should get you the desired result.

Answer 3

HttpUtil being deprecated, this is the correct method

StringBuffer url = req.getRequestURL();
String queryString = req.getQueryString();
if (queryString != null) {
    url.append('?');
    url.append(queryString);
}
String requestURL = url.toString();

Answer 4

// http://hostname.com/mywebapp/servlet/MyServlet/a/b;c=123?d=789

public static String getUrl(HttpServletRequest req) {
    String reqUrl = req.getRequestURL().toString();
    String queryString = req.getQueryString();   // d=789
    if (queryString != null) {
        reqUrl += "?"+queryString;
    }
    return reqUrl;
}