Fading a picture gradually (Python, Jython)

Answer 1

Find out what the scale is for the setBlue/Red/Green methods. I assume 0 corresponds to black, but what's the brightest? You seem to be assuming it's 1, but it might actually be 255 or something. Even if it is 1, it looks like this code isn't taking the pixel's old value into account, it's just setting it to an exact color, based on its vertical position. Maybe that's what you want, but I doubt it. You probably want to multiply the pixel's current value by something instead.

Answer 2

Let's look at just one line here:

setBlue(px,y*(2.0/h))

and key part here is

y*(2.0/h)

y changes, as you go down. Let's try some simple values for y and h. Let's say h is 100 and we will examine when y is both 0 and 50 (h/2). For y = 0, we get 0. For y = 50, we get 1. If your range of values for the colors is 256 with 0 being the darkest, then no wonder this is black. What you have is a range of values from 0. to 1., but I'm guessing what you want is to take that number and times it by the old color value.

What you want is:

setBlue(px,y*(2.0/h)*getBlue(px))

and similar things for the other colors.

Answer 3

To darken a pixel you multiply the red, green and blue levels by an appropriate fraction.

What you are doing:

setBlue(px,y*(2.0/h))

What you are being told to do:

setBlue(px,y*(2.0/h) * getBlue(px))