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Filter & Convert an Array into String using PHP

Answer 1

+2 A:

echo join(" ", array_map(create_function('$x', 'return $x->name;'), $arr));

Is one way of doing it

antennen 2010-02-17 18:34:45

for some reason I can't get this to work... I'm trying to figure it out

tim 2010-02-17 18:55:14

it doesn't work, because the "name" is under a number. $arr->##["name"]. And that number can be any number, like $arr->131["name"], $arr->113["name"]... you cannot refrence to it like $arr->name or $arr["name"]

tim 2010-02-17 19:14:38

That's the whole point of `array_map` - it's turning each term into `$x` for easier access. Please check the documentation on these functions before dismissing them.

ceejayoz 2010-02-17 19:25:21

I guess what I'm trying to say is - I'm trying to get past the "object", number 131, 112, 113, etc... and pull out the name from the object. I'm probably not making sense because of my lack of vocabulary... basically the arrays are stored under the objects, and I need to pull the "name" variable in the array, while I don't know that object name (object 131, 112, 113, etc...)

tim 2010-02-17 19:56:59

I found an error on my side, after fixing it, I'm getting the following error:Fatal error: Cannot use object of type stdClass as array in filename.php

tim 2010-02-17 20:23:39

Edited to work with your code. Note the -> instead of ["

antennen 2010-02-17 22:39:56

Answer 2

A:

$terms = array();
foreach($arr as $term) { $terms[] = $term->name; }
print implode($terms, ', ');

ceejayoz 2010-02-17 18:50:10

I got this error Fatal error: [] operator not supported for strings. I'm using drupal.

tim 2010-02-17 18:54:40

Sounds like there's an existing `$terms` variable. Change `$terms` to a different variable name, or do `$terms = array();` before this code.

ceejayoz 2010-02-17 19:08:39

The array() think helps pass the error, but I get a blank result. I think this statement is referencing to $arr->name, when it should reference to $arr->anynumber['name']

tim 2010-02-17 19:21:05

Nope. `foreach` steps through each item in `$arr` and turns it into `$term`, so `$term->name` is the correct notation. Try `print_r` ing `$term` to check.

ceejayoz 2010-02-17 19:24:09

print_r ing $term gave me the same results as $arr. print_r ing $terms gave me Array ( [0] => )

tim 2010-02-17 19:40:50

`print_r` ing `$term` cannot give the exact same results as `$arr`. Are you **sure** you're not seeing three separate `$term` `print_r` results, one after another? This is pretty straightforward PHP, so I'm rather baffled that you're having issues with both solutions proposed.

ceejayoz 2010-02-17 19:59:11

I found a mistake on my side... so after fixing it, print_r ing $term is giving me the object 113. and the following code: foreach($arr as $term) { $terms = array($term->name); }print implode($terms, ', '); gives me "wonderful"

tim 2010-02-17 20:20:59

You're doing the array() wrong. It needs to be done once, before the `foreach` loop, or you're wiping it out each time `foreach` runs. See my update to the answer.

ceejayoz 2010-02-17 20:29:42

You rock! It worked. Thanks for sticking with me the whole hour:)

tim 2010-02-17 20:37:06

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Filter & Convert an Array into String using PHP

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