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Question

Where would I run this validateForm method? I'm a very newbie PHP developer getting the hang of web developing.

Answer 1

A:

You have to add a name to your submit button :

  <input type="submit" value="enviar" name="validate" />

And after the declaration of validateForm

you put

if(getValue("validate") != "")
validateForm();

remi bourgarel 2010-02-19 15:49:57

This assumes that the submit button will be a successful control. It usually will be, but there are exceptions (especially once you leave this *specific* case). Better to use a hidden input.

David Dorward 2010-02-19 15:52:50

Answer 2

+1 A:

function validateForm(){
 if ( ) // Your form conditions go here
 {
    return true;
 } else {
    return false;
 }
} 
if ( $_GET ) // Only validate the form if it was submitted
{
   $validForm = validateForm();
} else {
   $validForm = false;
}

Examples for some conditions:

if ( !empty ( $_GET[ 'name' ] ) and !empty ( $_GET[ 'lastname' ] ) ) // Check if the user entered something in both fields

I can only recommend you to change your getValue function too.

It would be a good idea to change

return $_GET[$field];

to something like

return htmlspecialchars ( trim ( $_GET[$field] ) );

This will remove unnecessary whitespace and escape the output at once.

The next or probably first step you should take would be to change your form from GET to POST as it is, in most cases, a bad idea to send form data via GET.

lamas 2010-02-19 15:50:16

GET is useful if you want users to be able to bookmark certain areas. :) Thank you for your help. I used the trim() method as you suggested.

Serg 2010-02-19 16:23:15

Answer 3

A:

I'd check for the $_POST-variables in your getValue-function as you're trying to validate form-data (your checking $_GET-variables which is data submitted through the URL), you also may want to add "trim"
give the submit-button an id and check if the form has beed submitted that way

e.g. <input type="submit" value="enviar" id="submitButton" />

setting $validForm would look this this: $validForm = validateForm(); (instead of "$validForm = false;")

your validateForm-function should then check whether "$_POST["submitButton"]" is set and if your data is valid (set, right type, etc. etc.), if all of that is ok, return "true", otherwise "false"

Select0r 2010-02-19 15:50:21

Answer 4

A:

<html>
  <head>
  <?php
    $validForm = validateForm();

C.

symcbean 2010-02-19 15:55:00

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Where would I run this validateForm method? I'm a very newbie PHP developer getting the hang of web developing.

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