Let's suppose that I have the following class which tries to be immutable
public class Computation {
private final Operation operation;
private final double epsilon;
public Computation(Operation operation) {
this.operation = operation;
//Default value
epsilon = 0.01;
}
public Computation(Operation operation double epsilon) {
this(operation);
//Won't compile as epsilon is final and is set by the other constructor
this.epsilon = epsilon;
}
}
And, for the sake of the question, let's assume that I do not want to use a builder for this class (which would solve the issue).
So the question is:
Is there a way to achieve this behaviour without removing the final modifier to epsilon and keeping the two constructors?
That is, without doing something like
public class Computation {
private final Operation operation;
private final double epsilon;
public Computation(Operation operation Double epsilon) {
this(operation);
this.epsilon = (epsilon == null) ? 0.01 : epsilon;
}
}
and without using a builder
public class Computation {
private final Operation operation;
private final double epsilon;
private Computation(Builder builder) {
this.operation = builder.operation;
this.epsilon = builder.epsilon;
}
public static class Builder {
private final Operation operation;
//Default value
private double epsilon = 0.01;
public Builder(Operation operation) {
this.operation = operation;
}
public Builder epsilon(double epsilon) {
this.epsilon = epsilon;
return this;
}
public Computation build() {
return new Computation(this);
}
}