CakePHP pagination and the get parameters.

Question

Hi, I have a problem with the pagination in my search page. When a user search something I have a url like domain.com/search/?s=keyword but paginator gives me links like domain.com/search/page:x, so in the next and prev and numbers page the get parameter ist lost. I need to configure paginator to get links like domain.com/search/page:x/?s=keyword But I can't do this. I need to know how to configure $paginator->options(); $paginator->next(); $paginator->prev(); $paginator->numbers();

to get the needed efect. Thanx.

Answer 1

Basically you can do it like this:

function list_results($keywords)
  {
  $data = $this->paginate('Posts', array('Post.title LIKE' => '%'.$keywords.'%'));
  }

Answer 2

create the options array

$options = array('url'=> array('controller' => 'posts', 'action' => 'search', '?' => 'keyword='.$keyword));

set it to the helper

$paginator->options($options)

and then you can use the paginator helper while retaining the GET variables.

hope that it helped :)

Answer 3

To pass all URL arguments to paginator functions, add the following to your view: Plain Text View

$paginator->options(array('url' => $this->passedArgs));

That's it. See http://book.cakephp.org/view/166/Pagination-in-Views

Answer 4

http://q2interactive.net/view/retain-get-parameters-in-the-url-when-using-cakephp-paginator.html#comment-69

I used it, it works fine.

in app_controller file:

function _paginatorURL() { $passed = ""; $retain = $this->params['url']; unset($retain['url']); $this->set('paginatorURL',array($passed, '?' => http_build_query($retain))); }

function beforeFilter()
{

    $this->_paginatorURL();
    }

in views file:

  <?php $paginator->options = array( 'url' => $paginatorURL );?>

Hope it helps.