echo line returns in html source code

Question

How do you implement line returns when the html code is between simple quotes. The only way I found is to concatenate the line return between double quotes:

echo '<div>'."\n"
    .'<h3>stuff</h3>'."\n" 
    .'</div>'."\n";

Which lucks ugly to me.

Edit: The code between the simple quotes is quite long and with many attributes otherwise I would just use double quotes.

Answer 1

echo "<div>\n" .
    "<h3>stuff</h3>\n" .
    "</div>\n";

or

echo "<div>
    <h3>stuff</h3>
    </div>\n";

or

echo <<< HTML
    <div>
        <h3>stuff</h3>
    </div>
HTML;

But this is completely subjective.

Answer 2

You can do

echo "<div>\n<h3>stuff</h3>\n</div>\n";

or

echo '<div>
    <h3>stuff</h3>
</div>
';

Answer 3

Concatenation: echo '<div>' . "n";

Concatenation with constant: echo '<div>' . PHP_EOL;

Hard line feeds:

echo '<div>
';

End PHP mode: echo '<div>'; ?>

Double quotes: echo "<div>\n";

Heredoc:

echo <<<EOM
    <div>

EOM;

Answer 4

Single quotes inhibit backslash sequences. But newlines are pretty much optional outside of CDATA sections, so feel free to omit them.

Answer 5

echo <<<EOM
<div>
<h3 class="blabla" style='booboo' >stuff<h3>
</div>

EOM;

Using the <<< quotation, you don't need to escape any characters(they are simply outputted exactly how they are typed.