The problem is I am using get_info() to make a ajax call to Result.lasso and paste the response in div with id 'test'.I am unable to use the sendForm() function from the page where i am calling the get_info().
I have also tried using different versions of jQuery 1.1.1.3 is working fine.But i am facing the problem while using higher versions of jquery.
The error with higher versions is as follows
missing } in XML expression
[Break on this error] alert('hi');\n
test.lasso (line 3)
sendForm is not defined
[Break on this error] sendForm();
get_info() function definition
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js" type="text/javascript"></script>
<SCRIPT>
function get_info()
{
$.ajax({url: "Result.lasso", context: document.body, success: function(response){
document.getElementById('test').innerHTML = response ;},dataType:"script"});
}
</SCRIPT>
The code in Result.lasso is as follows
[Content_Type: 'text/html; charset=UTF-8']
<script type="text/javascript">
function sendForm()
{
alert('hi');
}
</script>
[Date]
form name= "abc" method = "get" action = "abcd.lasso">
input type ="text" name = "element1"/>
input type = "button" value="Click" onClick = "javascript: sendForm();"/>
</form>
Please help me out in resolving this problem
Thanks, Rajesh Konatham