I have this line in my program :
InputStream Resource_InputStream=this.getClass().getClassLoader().getResourceAsStream("Resource_Name");
But how can I get FileInputStream from it [Resource_InputStream] ?
views:
1229answers:
2
+3
A:
Use ClassLoader#getResource() instead.
URL resource = classLoader.getResource("Resource_Name");
File file = new File(resource.toURI());
FileInputStream input = new FileInputStream(file);
That said, I really don't see any benefit of doing so, or it must be required by a poor helper class/method which requires FileInputStream instead of InputStream. If you can, just use InputStream instead.
BalusC
2010-02-28 23:06:55
NB that technique won't work if the resource is in a JAR file, or on the network.
EJP
2010-02-28 23:13:29
@EJP: The requirement was to use a FileInputStream which itself requires... well a local file. So Balus' answer is limited but absolutely correct.
Willi
2010-02-28 23:22:24
The requirement was also to read from a resource. The two requirements can conflict.
EJP
2010-03-01 05:55:40
+1
A:
Long story short: Don't use FileInputStream as a parameter or variable type. Use the abstract base class, in this case InputStream instead.
Willi
2010-02-28 23:24:03